求两道分式题(过程额)

1.已知x/(x²-x 1)=1/3
所以3x=x^2-x 1
故x^2=4x-1
所以x^2/(x^4 x^2 1)
=x^2/[(4x-1)^2 4x]
=x^2/(16x^2-4x 1)
=x^2/(16x^2-x^2)
=1/15
2.(a^2 4a 4)/(a^3 2a^2-4a-8)
=(a 2)^2/[(a 2)^2*(a-2)]
=1/(a-2)

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