化简[1-(sin^4x-sin^2cos^2x cos^4x)/(sin^2)] 3sin^2x

sin^4x-sin^2xcos^2x cos^4x
=sin^4x 2sin^2xcos^2x cos^4x-3sin^2xcos^2x
=(sin^2x cos^2x)^2-3sin^2xcos^2x
=1-3sin^2xcos^2x
所以分子=3sin^2xcos^2x
所以原式=3sin^2xcos^2x/[sin^2x] 3sin^2x
=3cos^2x 3sin^2x
=3(sin^2x cos^2x)
=3

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