广义积分 (下限-1,上限1) ∫1/x^2+4x+5 dx=?具体步骤怎么算呢!

∫(-1~1) 1/(x² 4x 5) dx
= ∫(-1~1) 1/[(x 2)² 1],公式∫ 1/(x² a²) dx = (1/a)arctan(x/a)
= arctan(x 2) |(-1~1)
= arctan(1 2) - arctan(2 - 1)
= arctan(3) - arctan(1)
= arctan(3) - π/4
≈ 0.463648

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