解不等式:(1/5)^[ (log2 X)^2-1] < (1/5)^[ 2x(2 log底数为根号2 X)

(1/5)^[ (log2 X)^2-1] < (1/5)^[ 2x(2 log底数为根号2 X)=> (log2 X)^2-1 > 2x(2 log底数为根号2 X),令log2 X = y=>y^2 -1 > 4 2( log2X/log2根号2)=> y^2 > 5 4y => y> 5 => x > 32

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