求函数y=根号(1-2sinX) 1/(1 tanX)定义域

y=根号(1-2sinX) 1/(1 tanX)
1-2sinx≥0且1 tanX≠0,且tanx有意义
1-2sinx≥0 ==>sinx≤1/2 ==>2kπ-7π/6≤x≤2kπ π/6,k∈Z
tanx有意义 ==>x≠kπ π/2,k∈Z
1 tanX≠0 ==> x≠kπ-π/4,k∈Z
将上面的集合取交集得
函数定义域:
[2kπ-7π/6,2kπ-π/2)U(2kπ-π/2,2kπ-π/4)U(2kπ-π/4,2kπ π/6] ,k∈Z

更多阅读